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    United Bank of India

     

    Data Interpretation

    10 students viz. S1 through S10 gave a test that comprised of 20 questions viz. Q1 through Q20. The following table provides details about the students who attempted each of the given 20 questions. 
    http://www.complore.com/themes/fancy/qimages/DI2/image002.gif

    The age (in years) of students is one or the other of the three values 17, 18 and 19. The following table gives details of the age of the students. 

    http://www.complore.com/themes/fancy/qimages/DI2/image004.gif

    Q1) The number of students that have solved at least 7 questions an at most 10 questions is
    a. 56
    b. 6
    c. 9
    d. 7
    e. 8

    Q2) How many questions are attempted by at least three students who are not 17 years old?
    a. 11
    b. 9
    c. 8
    d. 12
    e. 10

    Q3) A question is said to be 'balanced', if the number of students who attempted the question and are 17 years old is same as the number of students who attempted the question and are 19 years old. How many such questions are there? 
    a. 3
    b. 4
    c. 5
    d. 6
    e. 7

    There are 10 states namely Delhi, Jharkhand, Bihar, Gujarat, Punjab, Haryana, Rajasthan, UP, MP and Orissa. Two out of the given 10 states are not connected with any of the given states with rail, whereas the remaining eight states are connected with exactly three of the given states with rail.
    Further it is known that: 
    1. Delhi is not connected to Gujarat and Rajasthan is not connected to MP by rail. 
    2. Bihar is connected to MP and Haryana is connected to Punjab by rail. 
    3. UP is connected to Delhi and Gujarat connected to Rajasthan by rail. 
    4. Delhi, Bihar and Punjab are not connected to each other by rail. 
    5. Haryana, UP and Rajasthan are not connected to each other by rail and Delhi is not connected to MP by rail.

    Q4) Which of the following two states are not connected to the other states with rail?
    a. Jharkhand and Delhi
    b. Delhi and Orissa
    c. Orissa and Jharkhand
    d. Rajasthan and Orissa
    e. Cannot be determined

    Q5) For which of the following state, the three states to which it is connected by rail can be exactly determined?
    a. UP
    b. MP
    c. Gujarat
    d. Delhi
    e. Punjab

    Q6) If Rajasthan is not connected to Punjab by rail but Bihar is connected to Haryana by rail, then which of the following is not possible?
    a. Gujarat is not connected to Punjab and Bihar by rail.
    b. Gujarat is not connected to Punjab and UP by rail.
    c. UP is not connected to Haryana and MP by rail.
    d. MP is not connected to Bihar and Punjab by rail.
    e. More than one of the given statements.

    There are 175 bags, each containing at least 63 and at most 99 pens. Also, no six bags contain the same number of pens.
    Q7)  What is the maximum possible number of pens put together in all the 175 bags together
    a. 7175
    b. 7375
    c. 7275
    d. 7475
    e. 7575

    Q8) What is the minimum possible number of pens put together in all the 175 bags together
    a. 6625
    b. 6675
    c. 6685
    d. 6695
    e. None of these.

    Answer the questions on the basis of the information given below.
    A money lender has 10 different bags namely Bag 1 through Bag 10. Each of the ten bags is filled with coins. Each coin in these ten bags is either of denomination 25 paise or 50 paise or Re. 1 or Rs. 2 or Rs. 5 or Rs. 10.The following table provides information about the number of coins of denomination 50 paise, Rs. 2 and Rs. 5 and the total number of coins in each of the ten mentioned bags.

    http://www.complore.com/themes/fancy/qimages/2009-08-26_0142.png
    Q9)In how many of the mentioned bags the total number of coins of denomination Rs. 10 is definitely 0?
    a. 0
    b. 1
    c. 2
    d. 3
    e. 4

    Q10) What can be the maximum possible worth of coins in any one out of the ten mentioned bags?
    a. Rs. 222
    b. Rs. 192
    c. Rs. 142
    d. Rs. 232
    e. Rs. 212

    Q11) What can be the minimum possible worth of coins in any one out of the ten mentioned bags?
    a. Rs. 24.5
    b. Rs. 32
    c. Rs. 36.5
    d. Rs. 40
    e. None of these.

    Q12) If the total worth of coins in the Bag 10 is Rs. 71, find number of coins of denomination Re. 1 in the Bag 10.
    a. 5
    b. 6
    c. 7
    d. 8
    e. Cannot be determined

    Five cricketers – P, Q, R, S and T were competing for ICC World Player of the Year. Each of them was rated on 5 different parameters, viz. A, B, C, D and E. The highest rating point being 5 and the lowest being 1. For each of the parameters, no two cricketers got the same rating.
    Overall scores for each of the cricketers was the sum total of the rating points in each of the parameters.
    P got the highest number of points, viz. 24.
    R was consistent in his scores i.e. he got the same number of points in 4 different parameters. 
    T got 5 in D and 3 in E.
    No two cricketers got the same total score and the final rankings were as follows:
    P, Q, R, S and T
     
    Q13) The difference of total points for two pairs of cricketers was the same. The 2 pairs were?
    a. Q and R, R and S
    b. P and Q, Q and R
    c. Q and S, R and T
    d. R and S, S and T
    e. Q and S, R and S

    Q14) The numbers of points managed by Q in D were?
    a. 5
    b. 4
    c. 1
    d. 2
    e. Cannot be determined

    Q15) The number of points managed by S in E were…
    a. 5
    b. 1
    c. 3
    d. 4
    e. Cannot be determined

    Q16) The number of cricketers who scored the same points in exactly 4 of the parameters was
    a. 1
    b. 2
    c. 3
    d. 4
    e. Cannot be determined

    One of the graph below represent the market share of five different brands of T.V sold in a particular city. The total number of TV sold was 25,000.
    The other one shows the unit sales price and the Tax the brand is subjected to. Tax is calculated on the sales price.

    Q17) What is the difference in number of units sold by the most popular brand and the second most popular brand ?                       
    a. 800
    b. 1000
    c. 1200
    d. 1400
    e. 1600

    Q18) Which Brand earned the maximum revenue before Tax ?                       
    a. A
    b. B
    c. C
    d. D
    e. E

    Q19) Which Brand earned the maximum revenue after Tax ?
    a. A
    b. B
    c. C
    d. D
    e. E

    Q20) Which Brand had to pay the Maximum Tax ?
    a. A
    b. B
    c. C
    d. D
    e. E

    Q21) The number of units sold of Brand A increased by 900 units in the next year, but the Market share of each Brand including Brand A remained the same. What would be the new total number of units sold? 
    a. 25000
    b. 30000
    c. 35000
    d. 40000
    e. 45000

    Q22) Which one of the following is true:   
                         
    a) The Brand which sold the maximum number of units paid the maximum Tax                        
    b) The Brand with highest unit cost paid the maximum Tax                        
    c) The brand with highest sales revenue before tax paid the maximum tax.                         
    d) The brand with highest Tax % paid the maximum Tax.         
    a. A
    b. B
    c. C
    d. D
    e. None of these

    Answers:-

    http://www.complore.com/themes/fancy/qimages/DI2/image006.gif

    1.The students who have attempted at least 7 questions and at most 10 questions are S1, S2, S3, S4, S7, S8, S9 and S10. Hence, 8 in number. Hence e.

    2. The questions that are attempted by at least three students who are not 17 years old are Q2, Q4, Q6, Q8, Q9, Q10, Q11, Q14, Q15, Q16, Q17 and Q 20. Hence, 12 in number.

    3. The questions who obey the condition given in the question Q4, Q5, Q13, Q17 and Q20 
    Hence,5 in number.        
                                                                                                                                                           

     From the information given in the question, the following table can be drawn 

                                      http://www.complore.com/themes/fancy/qimages/DI2/image0022.gif

    4.Since, each of the eight states viz. Delhi, Bihar, Gujarat, Punjab, Haryana, Rajasthan, UP and MP are connected to at least one other state by rail, we can conclude that Jharkhand and Orissa are the two states that are not connected to the other states by rail. 

    So, the possible states to which each state might be connected is given below. Remember that each state is connected to exactly three other states by rail. 
    Delhi: Haryana, Rajasthan and UP. 
    Bihar: Gujarat, Haryana, Rajasthan, UP and MP 
    Gujarat: Bihar, Punjab, Haryana, Rajasthan, UP and MP 
    Punjab: Gujarat, Haryana, Rajasthan, UP and MP 
    Haryana: Delhi, Bihar, Gujarat, Punjab, Haryana and MP 
    Rajasthan: Delhi, Bihar, Gujarat and Punjab . Hence c.

     

                                           http://www.complore.com/themes/fancy/qimages/DI2/image0042.gif
          UP: Delhi, Bihar, Gujarat, Punjab and MP 
    MP: Gujarat, Bihar, Punjab, Haryana and UP 

    So, for Delhi all the three states to which it is connected by rail can be exactly determined. Hence d.

    5.Given that Rajasthan is not connected to Punjab by rail but Bihar is connected to Haryana by rail. 
    The table will look like as follows: 

                                   http://www.complore.com/themes/fancy/qimages/DI2/image0062.gif

    Now, for Delhi, Bihar, Haryana and Rajasthan, the three states to which they are connected by rail. 

    Gujarat: Two states out of Punjab, UP and MP 
    Punjab: Two states out of Gujarat, UP and MP 
    UP: Two states out of Gujarat, Punjab and MP 
    MP: Two states out of Gujarat, Punjab and UP 

    Therefore, except for option (b) every other statement is possible.

     

    6.There are 99 – 63 + 1 = 37 different numbers between 99 and 63. 
    175/5 = 35. 

    7.So, maximum possible aggregate number of pens put together in all the 175 boxes = M 
    M = 5(99 + 98 +.....+ 66 + 65) 
    M = 5(99 x 50 – 32 x 65)/2 = 7175. Hence a.

    8.There are 99 – 63 + 1 = 37 different numbers between 99 and 63. 
    175/5 = 35. 

    9. The minimum possible number of pens put together in all the 175 boxes = N 
                 N = 5(63 + 64 +.....96 + 97) = 7175 – 5(99 + 98 – 64 – 63) = 7175 – 350 = 6825.hecen e.

                                                                                                                                                  
                             http://www.complore.com/themes/fancy/qimages/2009-08-26_0147.png

    There are two bags with the money lender, i.e. Bag 4 and Bag 9 in which the total number of coins of denomination Rs. 10 is definitely 0.hence c.

    10)
                                http://www.complore.com/themes/fancy/qimages/2009-08-26_0157.png
     
    Maximum possible worth of coins in Bag 1 is 40 + 18 x 10 = 40 + 180 = Rs. 220 (Assuming that there are 18 coins of denomination Rs. 10)
    Following the same logic the maximum possible worth of coins in bags 2, 3, 4, 5, 6, 7, 8, 9 and  10 is Rs. 54.5, Rs. 56.5, Rs. 56.5, Rs. 110.5, Rs. 69.5, Rs. 142, Rs. 124.5, Rs. 76 and Rs. 212 respectively.
    So, maximum possible worth of all the coins in any of the ten bags could be Rs. 212. Hence e

    11.Minimum possible worth of coins can be in the bag 2
    Minimum possible worth of coins in bag B can be Rs. 24.5 + Rs. (30/4) = Rs. 32
    Here we have assumed that there are 30 coins of denomination 25 paise in bag 2. Hence b.

    12.otal worth of coins of denomination 50 paise, Rs. 2 and Rs. 5 in the bag 10 = Rs. 62
    Since the total worth of all the coins in the bag 10 is Rs. 71, therefore the number of coins of denomination Rs. 10 is zero
    Let ‘a’ be the number of coins of denomination Re. 1 in the bag
    Therefore, the number of coins of denomination 25 paise in the bag 10 is 14 – a
    So, a + (15 – a)/4 = 71 – 62 = 9
    Therefore, the value of ‘a’ is 7.
    So, the number of coins of denomination Re.1 is 7. Hence c.

     

    13.We have the sum total of all the points with P, Q, R, S and T to be 75. Since, P was the one to score the highest number of points which were 24.
    So the total of points scored by Q, R, S and T was 51.
    The minimum possible number of points scored by T is 11.
    If T scores a minimum of 11, then S scores a minimum of 12 , R scores a minimum of 13 and Q scores a minimum of 14.The total amounts to 50.Now the extra 1 point can be adjusted such that Q scores 15 and the total will be 51.
    Now for 24 to be possible there is just one set of 5, 5, 5, 5, 4 points.
    If R scores 13, that means it is 4 * 3 + 1 or 4*2 + 5.The second case is neglected because 5 cannot be present for R  in any of the parameters. Hence it is the first case.
    So the table looks like

     

    A

    B

    C

    D

    E

     P

    5

    5

    5

    4

    5

    Q

     

     

     

     

     

    R

    3

    3

    3

    3

    1

    S

     

     

     

     

     

    T

    1

    1

    1

    5

    3

    Now S will have a minimum of 2 points in a, B and C each. That makes a minimum total of 6.The leftover 6 can be accommodated as 4 + 2 only.
    S can’t have a 5 in any of A, B, and C
    If S has exactly 2 4s in any of A, B, C, then in order to accommodate the leftover of 2, She needs two 1s, which is not possible
    If S has exactly 1 4 in any of A, B, C, then in order to accommodate the leftover of 4,She needs either (1,3) or (2,2). The former is not possible.
    That means it is set of 4, 2, 2, 2, 2 for S
    Thus in any case S scores 2 in D=> Q scores 1 in D.
     Hence Answer d

    14.We have the sum total of all the points with P, Q, R, S and T to be 75. Since, P was the one to score the highest number of points which were 24.
    So the total of points scored by Q, R, S and T was 51.
    The minimum possible number of points scored by T is 11.
    If T scores a minimum of 11, then S scores a minimum of 12 , R scores a minimum of 13 and Q scores a minimum of 14.The total amounts to 50.Now the extra 1 point can be adjusted such that Q scores 15 and the total will be 51.
    Now for 24 to be possible there is just one set of 5, 5, 5, 5, 4 points.
    If R scores 13, that means it is 4 * 3 + 1 or 4*2 + 5.The second case is neglected because 5 cannot be present for R  in any of the parameters. Hence it is the first case.
    So the table looks like

     

    A

    B

    C

    D

    E

     P

    5

    5

    5

    4

    5

    Q

     

     

     

     

     

    R

    3

    3

    3

    3

    1

    S

     

     

     

     

     

    T

    1

    1

    1

    5

    3

    Now S will have a minimum of 2 points in a, B and C each. That makes a minimum total of 6.The leftover 6 can be accommodated as 4 + 2 only.
    S can’t have a 5 in any of A, B, and C
    If S has exactly 2 4s in any of A, B, C, then in order to accommodate the leftover of 2, She needs two 1s, which is not possible
    If S has exactly 1 4 in any of A, B, C, then in order to accommodate the leftover of 4,She needs either (1,3) or (2,2). The former is not possible.
    That means it is set of 4, 2, 2, 2, 2 for S
    Thus in any case S scores 2 in D=> Q scores 1 in D.
    Hence Answer c.

    15.We have the sum total of all the points with P, Q, R, S and T to be 75. Since, P was the one to score the highest number of points which were 24.
    So the total of points scored by Q, R, S and T was 51.
    The minimum possible number of points scored by T is 11.
    If T scores a minimum of 11, then S scores a minimum of 12 , R scores a minimum of 13 and Q scores a minimum of 14.The total amounts to 50.Now the extra 1 point can be adjusted such that Q scores 15 and the total will be 51.
    Now for 24 to be possible there is just one set of 5, 5, 5, 5, 4 points.
    If R scores 13, that means it is 4 * 3 + 1 or 4*2 + 5.The second case is neglected because 5 cannot be present for R  in any of the parameters. Hence it is the first case.
    So the table looks like

     

     

    A

    B

    C

    D

    E

     P

    5

    5

    5

    4

    5

    Q

     

     

     

     

     

    R

    3

    3

    3

    3

    1

    S

     

     

     

     

     

    T

    1

    1

    1

    5

    3

    Now S will have a minimum of 2 points in a, B and C each. That makes a minimum total of 6.The leftover 6 can be accommodated as 4 + 2 only.
    S can’t have a 5 in any of A, B, and C
    If S has exactly 2 4s in any of A, B, C, then in order to accommodate the leftover of 2, She needs two 1s, which is not possible
    If S has exactly 1 4 in any of A, B, C, then in order to accommodate the leftover of 4,She needs either (1,3) or (2,2). The former is not possible.
    That means it is set of 4, 2, 2, 2, 2 for S
    Thus in any case S scores 2 in D=> Q scores 1 in D.
     Hence Answer e.

    16.e have the sum total of all the points with P, Q, R, S and T to be 75. Since, P was the one to score the highest number of points which were 24.
    So the total of points scored by Q, R, S and T was 51.
    The minimum possible number of points scored by T is 11.
    If T scores a minimum of 11, then S scores a minimum of 12 , R scores a minimum of 13 and Q scores a minimum of 14.The total amounts to 50.Now the extra 1 point can be adjusted such that Q scores 15 and the total will be 51.
    Now for 24 to be possible there is just one set of 5, 5, 5, 5, 4 points.
    If R scores 13, that means it is 4 * 3 + 1 or 4*2 + 5.The second case is neglected because 5 cannot be present for R  in any of the parameters. Hence it is the first case.
    So the table looks like

     

     

    A

    B

    C

    D

    E

     P

    5

    5

    5

    4

    5

    Q

     

     

     

     

     

    R

    3

    3

    3

    3

    1

    S

     

     

     

     

     

    T

    1

    1

    1

    5

    3

    Now S will have a minimum of 2 points in a, B and C each. That makes a minimum total of 6.The leftover 6 can be accommodated as 4 + 2 only.
    S can’t have a 5 in any of A, B, and C
    If S has exactly 2 4s in any of A, B, C, then in order to accommodate the leftover of 2, She needs two 1s, which is not possible
    If S has exactly 1 4 in any of A, B, C, then in order to accommodate the leftover of 4,She needs either (1,3) or (2,2). The former is not possible.
    That means it is set of 4, 2, 2, 2, 2 for S
    Thus in any case S scores 2 in D=> Q scores 1 in D.
    Hence Answer 3

    17.Most popular Brand is Brand D and after that it is Brand C as is clear from the Pie chart. Brand D sold = 26 % and Brand C sold = 22 % . So the difference is 4% of Total Market = 25,000*4/100 = 1,000. Hence b.

     

    18.Revenue earned Before tax = Number of Units sold * Unit Price
    Revenue earned by Brand A = (18*25000/100 ) * 14,500= 65,250,000
    Revenue earned by Brand B = (14*25000/100 ) * 16,000= 56,000,000
    Similarly the revenue earned by C = 66,000,000.
    Revenue earned by D= (26*25000/100)*13,000= 84,500,000
    Revenue earned by E= 67,500,000
    So maximum revenue is earned by D. hence d.

     

    19.Revenue earned after Tax = Revenue earned before Tax -Tax

    SALES Tax % Tax paid Revenue
    BRAND A 65,250,000      149,135,000     56,115,000
    BRAND B 56,000,000      116,160,000     49,840,000
    BRAND C 66,000,000      106,600,000     59,400,000
    BRAND D 84,500,000       97,605,000      76,895,000
    BRAND E 67,500,000       117,425,000    60,075,000
    TOTAL      339,250,000     36,925,000      302,325,000
    So Brand D earned the maximum revenue after Tax. Hence d.

    20.From above table it is clear that BRAND A paid the maximum tax. Hence a.

     

    21.Present share of market by Brand A= 18 % of 25,000 = 4,500 units.
    If it increases by 900 it will be 4,500+900 = 5,400
    As the market share of A remained the same that is 18 % we have 18 % of X = 5,400
    so X = 5,400*100/18 = 30,000. Hence b.

    22.Only Statement d is correct. Hence d.

     

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